Question
Download Solution PDF50 सेकंदात एक ट्रेन 600 मीटर लांबीचा फलाट ओलांडते. हे 60 सेकंदात आणखी 900 मीटर लांबीचे
प्लॅटफॉर्म ओलांडते. ट्रेनची लांबी व वेग किती आहे?Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFवापरलेले सूत्र:
घेतलेला वेळ = अंतर / वेग
गणना:
समजा ट्रेनची लांबी x आहे
\(\Rightarrow {\rm{}}\frac{{600\; + \;x}}{{50}} = \frac{{900\; +\; x}}{{60}}\)
⇒ 3600 + 6x = 4500 + 5x
⇒ x = 900 मीटर
\(\Rightarrow {\rm{}}Speed = \frac{{600\; + \;900}}{{50}} = 30\;m/sec.\)
⇒ वेग = 30 × 18/5 = 108 किमी / ता
∴ ट्रेनची लांबी आणि वेग 900 मीटर आणि 108 किमी / ता आहे.
1 किमी / ताशी = 5/18 मीटर / सेकंद
Last updated on Jun 26, 2025
-> SSC MTS 2025 Notification has been released by the Staff Selection Commission (SSC) on the official website on 26th June, 2025.
-> A total of 1075 Vacancies have been announced for the post of MTS and Havaldar in CBIC and CBN.
-> The last date to apply online will be 25th July 2025 as per the SSC Exam Calendar 2025-26.
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-> Candidates with basic eligibility criteria of the 10th class were eligible to appear for the examination.
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