In the given figure, PQRS is a trapezium in which PM || SN, NR = 9 cm, PS = 12 cm, QM = NR and NR = SN. What is the area (in cm2) of trapezium?

01.02.2018.003

This question was previously asked in
SSC CGL Previous Paper 5 (Held On: 8 August 2017 Shift 2)
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  1. 170
  2. 182
  3. 189
  4. 191

Answer (Detailed Solution Below)

Option 3 : 189
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Detailed Solution

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Given:

PS = 12 cm

NR = 9 cm

QM = NR and NR = SN

Formula Used:

Area of Trapezium = (1/2) × (Sum of Parallel Sides) × Height

Calculation:

According to the question,

QM = NR and NR = SN

⇒ QM = NR = SN = 9 cm

Again according to the question,

PM || SN

⇒ PS = MN = 12 cm

In trapezium PQRS,

QR = QM + MN + NR

⇒ QR = 9 + 12 + 9 = 30 cm

Height = SN = 9 cm

Area of Trapezium = (1/2) × (PS + QR) × SN

⇒ Area of Trapezium = (1/2) × (12 + 30) × 9

⇒ Area of Trapezium = (1/2) × (12 + 30) × 9

⇒ Area of Trapezium = 189 cm2

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