In PCM, if the number of quantization levels is increased from 4 to 64, then the bandwidth requirement will approximately be:

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  1. 4 times
  2. 16 times
  3. 8 times
  4. 3 times

Answer (Detailed Solution Below)

Option 4 : 3 times

Detailed Solution

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Concept:

The number of levels for an n-bit PCM system is given by:

L = 2n

We can also state that the number of bits for a given quantization level will be:

n = log2 L

Also, the bandwidth of PCM is given by:

\(BW=n{f_s}\)

n = number of bits to encode

fs = sampling frequency

Calculation:

For L = 4 quantization levels, the number of bits n = log2 4 = 2 bits. The bandwidth is, therefore:

B.W. = 2 fs

Similarly, For L = 64 quantization levels, the number of bits n = log2 64 = 6 bits. The bandwidth is, therefore:

B.W. = 6 fs

Clearly, the Bandwidth is increased by 3 times.

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