Question
Download Solution PDFIn PCM, if the number of quantization levels is increased from 4 to 64, then the bandwidth requirement will approximately be:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The number of levels for an n-bit PCM system is given by:
L = 2n
We can also state that the number of bits for a given quantization level will be:
n = log2 L
Also, the bandwidth of PCM is given by:
\(BW=n{f_s}\)
n = number of bits to encode
fs = sampling frequency
Calculation:
For L = 4 quantization levels, the number of bits n = log2 4 = 2 bits. The bandwidth is, therefore:
B.W. = 2 fs
Similarly, For L = 64 quantization levels, the number of bits n = log2 64 = 6 bits. The bandwidth is, therefore:
B.W. = 6 fs
Clearly, the Bandwidth is increased by 3 times.
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