Question
Download Solution PDFIn nine games, A wins five games with score differences of 12, 3, 8, 4 and 1, while in the remaining four games, he loses with score differences of –4, –1, –2 and –3. The average score difference of A in all the nine games is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
A wins five games with score differences of 12, 3, 8, 4, and 1.
A loses four games with score differences of -4, -1, -2, and -3.
Formula Used:
Average score difference = Total score difference / Number of games
Calculation:
Total score difference = 12 + 3 + 8 + 4 + 1 - 4 - 1 - 2 - 3
⇒ Total score difference = 18
Number of games = 9
Average score difference = Total score difference / Number of games
⇒ Average score difference = 18 / 9
⇒ Average score difference = 2
The average score difference of A in all the nine games is 2.
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