In how many ways can a student choose (n - 2) courses out of n courses if 2 courses are compulsory (n > 4)? 

This question was previously asked in
NDA-II 2024 (Maths) Official Paper (Held On: 01 Sept, 2024)
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  1. (n - 3) (n - 4)
  2. (n - 1) (n - 2)
  3. (n - 3) (n - 4)/2
  4. (n - 2) (n - 3)/2

Answer (Detailed Solution Below)

Option 4 : (n - 2) (n - 3)/2
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Detailed Solution

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Explanation:

Given,

Number of courses, n > 4

The student needs to choose (n - 2) courses out of n courses, with 2 courses being compulsory

∴Total courses is n – 2 and total remaining courses that can be chosen from (n – 2) courses is ( n – 4).

∴ Required number of ways (n-2) C (n-4).

⇒ \(\frac{(n-2)(n-3)}{2}\)
 

∴ Option d is correct.
(n2)×(n3)

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