In a source follower or common drain amplifier, the voltage gain (AV) is

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UPSC ESE (Prelims) Electronics and Telecommunication Engineering 19 Feb 2023 Official Paper
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  1. \(A_V=\frac{g_{m 1}}{g_{m 1}+g_{s 1}+\left(g_{d s 1}+g_{d s 2}\right) / 2}\)
  2. \(A_V=\frac{g_{d s 1}}{g_{m 1}+g_{s 1}+\left(g_{d s 1}+g_{d s 2}\right)}\)
  3. \(A_V=\frac{g_{m 1}}{g_{m 1}+g_{s 1}+g_{d s 1}+g_{d s 2}}\)
  4. \(A_V=\frac{g_{m 1}}{2\left(g_{m 1}+g_{s 1}\right)+g_{d s 1}+g_{d s 2}}\)

Answer (Detailed Solution Below)

Option 1 : \(A_V=\frac{g_{m 1}}{g_{m 1}+g_{s 1}+\left(g_{d s 1}+g_{d s 2}\right) / 2}\)
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Detailed Solution

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  • In a source follower or common drain amplifier, the voltage gain (AV) is close to option 1.
  • This is because these amplifier configurations are designed to have unity voltage gain, meaning that the output voltage closely follows the input voltage without significant amplification.
  • The primary purpose of such configurations is often to provide impedance matching or to act as a buffer between different stages of a circuit.

Vgs2 = V0 - Vs2 =V0

Vgs1= V- V0

V0 gd- gm1 Vgs1 + gm2 Vgs2 + V0 gds2 = 0

Option 1 is correct.

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