Question
Download Solution PDFIn a race, an athlete covers a distance of 366 m in 61 sec in the first lap. He covers the second lap of the same length in 183 sec. What is the average speed (in m/sec) of the athlete?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Distance of the first lap (D1) = 366 m
Time for the first lap (T1) = 61 sec
Distance of the second lap (D2) = 366 m
Time for the second lap (T2) = 183 sec
Formula used:
Average Speed = Total Distance / Total Time
Calculation:
Total Distance = D1 + D2 = 366 + 366 = 732 m
Total Time = T1 + T2 = 61 + 183 = 244 sec
⇒ Average Speed = 732 / 244
⇒ Average Speed = 3 m/sec
∴ The correct answer is option 4.
Last updated on Jun 2, 2025
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