Question
Download Solution PDFIn a paged memory, the page hit ratio is 0.40. The time required to access a page in secondary memory is equal to 120 ns. The time required to access a page in primary memory is 15 ns.
The average time required to access a page is.Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Hit ratio:
When a page is found in the main memory, then it is known as hit.
Hit radio is defined as the ratio of total number of hits to the sum of total number of hit and misses.
In miss, when a page is not in main memory, it is found in secondary memory.
Formula:
Effective average access time = hit ratio × access time for main memory + miss ratio × access time for secondary memory
Explanation:
Hit ratio = 0. 40
Access time for secondary memory = 120 ns
Access time in primary memory = 15 ns
Effective average access time = 0.40 × 15 + 0.60 × 120
= 6 + 72 = 78 nsLast updated on Jun 12, 2025
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