In a fixed bias circuit silicon n-p-n transistor (CE) with β = 90 is used. If V_CC= 15 V, R_C= 3 kΩ and R_B = 1 MΩ, the V_CE at Q-point is given as:

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In a fixed bias circuit silicon n-p-n transistor (CE) with β = 90 is used. If V_CC= 15 V, R_C= 3 kΩ and R_B = 1 MΩ, the V_CE at Q-point is given as:

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KVS TGT WET (Work Experience Teacher) 23 Dec 2018 Official Paper

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12.41 V
7.5 V
10.0 V
11.6 V

Answer 1

Concept:

Fixed Base Biasing a Transistor:

The circuit shown is called as a “fixed base bias circuit”, because the transistor's base current, I_B remains constant for given values of V_cc, and therefore the transistor operating point must also remain fixed.

This two-resistor biasing network is used to establish the initial operating region of the transistor using a fixed current bias.

Calculation:

Given;

β = 90

VCC = 15 V

RC = 3 kΩ

RB = 1 MΩ

Then

\(I_{B} = \frac{V_{CC}- V_{BE}}{R_{B}}=\frac{15-0.7}{1 M\Omega} =14.3 \, \mu A\)

and

\(I_{C}=\beta I_{B} = 90 \times 14.3 = 1287 \, \mu A=1.287 \, mA\)

Therefore;

\(V_{CE} = V_{CC} - I_{C}R_{C} = 15 - (1.287 \times 3)=11.137\,V \approx 11.6 \, V\)

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Question

In a fixed bias circuit silicon n-p-n transistor (CE) with β = 90 is used. If V_CC= 15 V, R_C= 3 kΩ and R_B = 1 MΩ, the V_CE at Q-point is given as:

Answer (Detailed Solution Below)

Detailed Solution

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Question

In a fixed bias circuit silicon n-p-n transistor (CE) with β = 90 is used. If VCC = 15 V, RC = 3 kΩ and RB = 1 MΩ, the VCE at Q-point is given as:

Answer (Detailed Solution Below)

Detailed Solution

More Biasing of Transistors Questions

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More Analog Electronics Questions

In a fixed bias circuit silicon n-p-n transistor (CE) with β = 90 is used. If V_CC= 15 V, R_C= 3 kΩ and R_B = 1 MΩ, the V_CE at Q-point is given as: