Question
Download Solution PDFIf z = 2i + 1, find the value of \(\rm\left| z + \overline z +1\over z + \overline z -1\right|\), where \(\rm \overline z\) is the conjugate of the complex number z
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The modulus of a complex number z = x + iy
|z| = \(\rm \sqrt{x^2+y^2}\)
The conjugate \(\rm \overline z\) = x - iy
Calculation:
z = 1+ 2i
\(\rm \overline z\)= 1 - 2i
S = \(\rm\left| z + \overline z +1\over z + \overline z -1\right|\)
S = \(\rm\left| 1+2i+1-2i+1\over 1+2i+1-2i -1\right|\)
S = \(\rm\left| 3\over 1\right|\)
S = 3
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