If the object is placed between infinity and optical centre O of the concave lens, how will the image be formed after refraction?

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RRB JE Previous Paper 3 (Held On: 22 May 2019 Shift 1)
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  1. Diminished
  2. Point size
  3. Of same size
  4. Enlarged

Answer (Detailed Solution Below)

Option 1 : Diminished
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CONCEPT:

  • The transparent curved surface which is used to refract the light and make an image of any object placed in front of it is called a lens.
  • The lens whose refracting surface is upside is called a convex lens and the lens whose refracting surface is inside is called a concave lens or diverging lens.
    • Concave lenses diverge light rays and hence are also called diverging lenses.

Positions of the object and image:

F1 Savita Teaching 19-7-24 D10F1 Savita Teaching 19-7-24 D11

Position of the object Position of the image The relative size of the image Nature of the image
1. At infinity At focus F1 Highly diminished, point-sized Virtual and erect
2. Between infinity and optical center O of the lens Between focus F1 and optical center O Diminished Virtual and erect

EXPLANATION:

  • When the object is between the infinity and optical center of the lens then the image forms between focus and optical center which is diminished, virtual and erect. So option 1 is correct.
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