If the bulk modulus is K, modulus of Elasticity is E and Poisson’s ratio is \(\frac{1}{m}\), then which of the following is true ?

Question

Question

This question was previously asked in

UKPSC JE Mechanical 2013 Official Paper I

Answer 1

Explanation:

The relation between Young’s modulus (E), rigidity modulus (G) and poison’s ratio (μ) is given by

E = 2G (1 + μ)

Some other important relations are as follows:

E = 3K (1 - 2μ)

\({\bf{E}} = \frac{{9{\bf{KG}}}}{{3{\bf{K}} + \;{\bf{G}}}}\)

Here, Poission ratio (μ) = \(\frac 1m\)

Therefore, \(E = 3K (1 – 2μ)=3K(1-\frac2m) \)