If a sin2 θ + b cos2 θ = c, then tan2 θ = ?

This question was previously asked in
AAI ATC Junior Executive 21 Feb 2023 Shift 2 Official Paper
View all AAI JE ATC Papers >
  1. \(\frac{b-c}{a-c}\)
  2. \(\frac{c-b}{a-c}\)
  3. \(\frac{a-c}{c-b}\)
  4. \(\frac{a-c}{b-c}\)

Answer (Detailed Solution Below)

Option 2 : \(\frac{c-b}{a-c}\)
Free
AAI ATC JE Physics Mock Test
6.1 K Users
15 Questions 15 Marks 15 Mins

Detailed Solution

Download Solution PDF

Given:

a sin2 θ + b cos2 θ = c

Concept:

Use formula :

sec2 θ = 1 + tan2 θ

Calculation:

a sin2 θ + b cos2 θ = c

Divide by cos2 θ both the sides then

⇒ a tan2 θ + b = c sec2 θ

⇒ a tan2 θ + b = c (1 + tan2 θ)

⇒ (a - c) tan2 θ = c - b

\(\rm \implies tan^2\theta=\frac{c-b}{a-c}\)

Hence the option (2) is correct.

Latest AAI JE ATC Updates

Last updated on May 26, 2025

-> AAI ATC exam date 2025 will be notified soon. 

-> AAI JE ATC recruitment 2025 application form has been released at the official website. The last date to apply for AAI ATC recruitment 2025 is May 24, 2025. 

-> AAI JE ATC 2025 notification is released on 4th April 2025, along with the details of application dates, eligibility, and selection process.

-> Total number of 309 vacancies are announced for the AAI JE ATC 2025 recruitment.

-> This exam is going to be conducted for the post of Junior Executive (Air Traffic Control) in Airports Authority of India (AAI).

-> The Selection of the candidates is based on the Computer Based Test, Voice Test and Test for consumption of Psychoactive Substances.

-> The AAI JE ATC Salary 2025 will be in the pay scale of Rs 40,000-3%-1,40,000 (E-1).

-> Candidates can check the AAI JE ATC Previous Year Papers to check the difficulty level of the exam.

-> Applicants can also attend the AAI JE ATC Test Series which helps in the preparation.

Get Free Access Now
Hot Links: teen patti master teen patti casino apk teen patti master app teen patti plus teen patti noble