If a − b = 5 and ab = 25, then the value of a− bis:

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SSC Selection Post 2024 (Higher Secondary Level) Official Paper (Held On: 25 Jun, 2024 Shift 2)
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  1. 525
  2. 400
  3. 450
  4. 500

Answer (Detailed Solution Below)

Option 4 : 500
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SSC Selection Post Phase 13 Matriculation Level (Easy to Moderate) Full Test - 01
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Detailed Solution

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Given:

If a - b = 5 and ab = 25

Formula used:

a3 - b3 = (a - b)(a2 + ab + b2)

Calculation:

a - b = 5

ab = 25

(a - b)2 = a2 - 2ab + b2

⇒ 52 = a2 - 2×25 + b2

⇒ 25 = a2 - 50 + b2

⇒ a2 + b2 = 75

a3 - b3 = (a - b)(a2 + ab + b2)

⇒ a3 - b3 = 5(75 + 25)

⇒ a3 - b3 = 5×100

⇒ a3 - b3 = 500

∴ The correct answer is option 4.

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