Question
Download Solution PDFIf 2sin(3x -15)° = 1, 0° < (3x - 15) < 90°, then find the value of cos2(2x +15)° + cot2 (x + 15)°.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
2sin(3x -15)° = 1
Calculation:
sin(3x - 15)° = 1/2
⇒ sin (3x - 15)° = sin 30°
⇒ (3x - 15)° = 30°
⇒ 3x = 30° + 15° = 45°
⇒ x =
Then,
cos2(2x +15)° + cot2 (x +15)°
cos2(2 × 15 +15)° + cot2 (15 +15)°
⇒ cos2(45)° + cot2(30)°
⇒
⇒
∴ cos2(2x +15)° + cot2 (x +15)° =
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