(i2 + i4 + i6 +... + i2n) का मान क्या है? जहाँ n सम संख्या है।

  1. 1
  2. 0
  3. -1
  4. उपरोक्त में से कोई नहीं 

Answer (Detailed Solution Below)

Option 2 : 0
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Detailed Solution

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संकल्पना:

i2 = -1

i3 = - i

i4 = 1

i4n = 1

गणना:

हमें (i2 + i4 + i6 +... + i2n) का मान ज्ञात करना है

(i2 + i4 + i6 +... + i2n) = (i2 + i4) + (i6 + i8) + …. + (i2n-2 + i2n)

= (-1 + 1) + (-1 + 1) + …. (-1 + 1)

= 0 + 0 + …. + 0

= 0

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