Question
Download Solution PDFN सिग्नलों को प्रसारित करने के लिए समय विभाजन बहुसंकेतन द्वारा fm Hz तक सीमित प्रत्येक बंध को न्यूनतम कितने बैंडविड्थ की आवश्यकता होगी?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसूत्र: समय विभाजन बहुसंकेतक (TDM) के लिए न्यूनतम बैंडविड्थ को निम्न द्वारा ज्ञात किया गया है -
जहाँ, Rb = Nnfs
N = सिग्नलों की संख्या
n = बिटों की संख्या
fs = प्रतिचयन आवृत्ति = 2 × fm
fm = msg सिग्नल बैंडविड्थ
हल:
दिया गया है:
fm बैंडविड्थ के साथ N सिग्नल।
TDM न्यूनतम B.W = Nnfm
माना कि n = 1 बिट
BWmin = Nfm
Last updated on May 30, 2025
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