समीकरण 3x + 2y - 6z = 1, 2x - 3y + 3z = -1, x - 4y + z = -6 के निकाय हल है?

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  1. (1, -2, 1)
  2. (1, 1, 2)
  3. (2, 1, 1)
  4. (1, 2, 1)

Answer (Detailed Solution Below)

Option 4 : (1, 2, 1)
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दिया गया है:

समीकरणों 3x + 2y - 6z = 1, 2x - 3y + 3z = -1, x - 4y + z = - 6 के निकाय

अवधारणा:

चरों के उन्मूलन की अवधारणा का प्रयोग कीजिए।

गणना:

समीकरणों का निकाय -

3x + 2y - 6z = 1

2x - 3y + 3z = -1

x - 4y + z = -6

3x + 2y - 6z = 1 के लिए x को अलग करें,

अब अन्य समीकरणों में प्रतिस्थापित करें,

और

सरलीकरण के बाद,

और

अब, के लिए y को अलग करें,

अब अन्य समीकरण में प्रतिस्थापित करें,

⇒ z = 1

के लिए,

z = 1 प्रतिस्थापित करने पर,

⇒ y = 2

के लिए,

z = 1, y = 2 प्रतिस्थापित करने पर,

⇒ x = 1

समीकरणों के निकाय का हल हैं:

x = 1, y = 2, z = 1

अतः विकल्प (4) सही है।

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