सांख्यिकी की समस्या समान मानक के दो खंडों में दी गई है। समस्या को हल करने के लिए खंड x के लिए संभावना 4 ∶ 3 हैं और समान समस्याओं को हल करने के लिए खंड Y के लिए संभावना 7 : 8 हैं। यदि दोनों खंड एक दूसरे से स्वतंत्र प्रयास करते हैं, तो कोई भी खंड आंकड़ों की समस्या को हल नहीं करता है, इस बात की प्रायिकता है:

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SSC CGL JSO Tier-II, 2018 (Statistics) Official Paper-III (Held On: 14 Sept, 2019)
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PYST 1: SSC CGL - General Awareness (Held On : 20 April 2022 Shift 2)
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व्याख्या

सांख्यिकी की समस्या समान मानक के दो खंडों में दी गई है

समस्या को हल करने के लिए खंड x के लिए संभावना = 4 : 3

⇒ 4/4+ 3

⇒ 4/7

⇒ समस्या को हल करने के लिए खंड y के लिए संभावना = 7 : 8

⇒ 8/8 + 7

⇒ 8/15

लेकिन इस बात प्रायिकता कि कोई भी खंड इन समस्याओं को हल नहीं करता है

यदि दोनों खंड एक दूसरे से स्वतंत्र हैं तो नकारात्मक प्रायिकता

P(X ∩ Y) = P(X).P(Y)

⇒ (4/7) × 8/15

⇒ 32/105

∴ यदि दोनों खंड एक दूसरे से स्वतंत्र प्रयास करते हैं, तो कोई भी खंड आंकड़ों की समस्या को हल नहीं करता है, इस बात की प्रायिकता​ 32/105 है।

Alternate Method Concept:

Calculation:

Given:

Odds against section X to solve the problem

Probability of not solving:

Odds in favour of Y to solve a probelm:

Problem of solving from Y will be

Problem of not solving by Y will be

The probability that neither section solves the problems will be

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