36 स्टेटर स्लॉट वाले एक 3 - चरण, 4 ध्रुव वाले तुल्यकालिक मशीन के तीसरे हार्मोनिक emf के लिए चौड़ाई कारक क्या है?

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ESE Electrical 2016 Paper 2: Official Paper
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  1. 0.47
  2. 0.53
  3. 0.67
  4. 0.73

Answer (Detailed Solution Below)

Option 3 : 0.67
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चौड़ाई कारक या एक वितरण कारक को निम्न द्वारा ज्ञात किया गया है

\({k_d} = \frac{{\sin n \cdot \frac{{m\beta }}{2}}}{{m \cdot \sin \frac{{n\beta }}{2}}}\)          (nवें हार्मोनिक के लिए)

m = प्रति चरण प्रति ध्रुव स्लॉटों की संख्या 

β = स्लॉट कोण 

गणना:

3 - चरण, 4 - ध्रुव वाला तुल्यकालिक मशीन। 

स्लॉट की संख्या = 36 (स्टेटर स्लॉट)

\(m = \frac{{36}}{{3\; \times \;4}} = 3\)

\(\beta = \frac{{180^\circ }}{{slots\;per\;pole}}\)

\(\beta = \frac{{180^\circ }}{{36/4}} = 20^\circ \)

इसलिए, \({k_d} = \frac{{\sin \frac{{\left( 3 \right)\left( 3 \right)\; \times \;20^\circ }}{2}}}{{3\sin \frac{{3\; \times \;20}}{2}}}\)

\(\Rightarrow {k_d} = \frac{{\sin 90^\circ }}{{3\sin 30^\circ }} = \frac{2}{3}\)

⇒ kd = 0.67

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