Question
Download Solution PDFयदि f(x) = [x]² - 30[x] + 221 = 0, जहाँ [x] महत्तम पूर्णांक फलन है, तो सभी पूर्णांक हलों का योग क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFव्याख्या:
f(x) = [x]² - 30[x] + 221 = 0
⇒ [x] = \(\frac{30± \sqrt{900-884}}{2} = \frac{30±4}{2}\)
⇒ [x] = \(\frac{30+ 4}{2 }, \frac{30 -4 }{2}\)
⇒ [x] = 17 , 13
इस प्रकार, f(x) के पूर्णांक हलों का योग 30 है।
∴ विकल्प (d) सही है
Last updated on May 30, 2025
->UPSC has released UPSC NDA 2 Notification on 28th May 2025 announcing the NDA 2 vacancies.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced for cycle 2. The written examination will be held on 14th September 2025.
-> Earlier, the UPSC NDA 1 Exam Result has been released on the official website.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.