Question
Download Solution PDFमाना ABCDEF एक नियमित षट्भुज है। यदि \(\rm \vec{AD}=m \vec {BC}\ और\ \vec {CF}=n\vec {AB}\) है, तो mn का मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFगणना:
\( \vec{AB} = 2\vec{FC} \)
⇒ \( \vec{AB} = -2\vec{CF} \)
⇒ \( n = -\frac{1}{2} \)
इसके अलावा,
\( \vec{AD} = 2\vec{BC} \Rightarrow m = 2 \)
अब,
\( mn = 2 \left( -\frac{1}{2} \right) = -1 \)
∴ mn का अंतिम मान -1 है।
Last updated on May 30, 2025
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