यदि  है, तब:

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SSC CGL 2022 Tier-I Official Paper (Held On : 13 Dec 2022 Shift 3)
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Answer (Detailed Solution Below)

Option 2 :
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PYST 1: SSC CGL - General Awareness (Held On : 20 April 2022 Shift 2)
25 Qs. 50 Marks 10 Mins

Detailed Solution

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दिया गया है:

tan2 θ + tan4 θ = 1

प्रयुक्त अवधारणा:

tan2 θ + 1 = sec2 θ

गणना:

⇒ tan2 θ + tan4 θ = 1

⇒ tan2 θ (1 + tan2 θ) = 1

⇒ tan2 θ × sec2 θ = 1

⇒ tan2 θ = 1/sec2 θ = cos2 θ 

अब tan2 θ का मान समीकरण में रखने पर:

⇒ tan2 θ + tan4 θ = 1

⇒ tan2 θ + (tan2)2 θ = 1

⇒ cos2 θ + (cos2)2 θ = 1

⇒ cos2 θ + cos4 θ = 1

∴ सही विकल्प 2 है।

Latest SSC CGL Updates

Last updated on Jul 7, 2025

-> The SSC CGL Notification 2025 for the Combined Graduate Level Examination has been officially released on the SSC's new portal – www.ssc.gov.in.

-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.

-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.

->  Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.

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