यदि x + y + z = 4 और x2 + y2 + z2 = 12 है, तो xy + yz + xz ज्ञात कीजिए।

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SSC CGL 2023 Tier-I Official Paper (Held On: 20 Jul 2023 Shift 2)
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  1. 4
  2. 6
  3. 7
  4. 2

Answer (Detailed Solution Below)

Option 4 : 2
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प्रयुक्त सूत्र

(x + y + z)2 = x2 + y2 + z2 + 2(xy + yz + zx)

गणना

x + y + z = 4

दोनों पक्षों का वर्ग करने पर

⇒ (x + y + z)2 = 42

⇒ x2 + y2 + z2 + 2(xy + yz + zx) = 16

⇒ 2(xy + yz + zx) = 16 – 12

⇒ xy + yz + zx = 2

उत्तर 2 है

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