यदि f(2x) = 4x2 + 1 है, तो x के कितने वास्तविक मानों के लिए f(2x), f(x) और f(4x) का गुणोत्तर माध्य (GM) होगा?

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NDA-II 2024 (Maths) Official Paper (Held On: 01 Sept, 2024)
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  1. चार
  2. दो
  3. एक
  4. कोई नहीं

Answer (Detailed Solution Below)

Option 3 : एक
Free
NDA 01/2025: English Subject Test
30 Qs. 120 Marks 30 Mins

Detailed Solution

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व्याख्या:

f(2x) = 4x2 + 1

⇒f(x) = x2 + 1

⇒ f(4x) = 16x2 + 1

⇒ (4x2 + 1)2 = (x2 + 1) × (16x2 + 1) [f(2x), f(x) और f(4x) का GM है]

⇒ 16x4 + 8x2 + 1 = 16x4 + x2 + 16x2 + 1

⇒ 16x4 + 8x2 + 1 = 16x4 + 17x2 + 1

⇒ 9x2 = 0

⇒x2 = 0

⇒x = 0

इस प्रकार x का एक वास्तविक मान संभव है

∴ विकल्प (c) सही है।

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