Question
Download Solution PDFश्रृंखला 22 + 42 + 62 + .... + (2n)2 का योग ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
प्रथम n प्राकृत संख्याओं के वर्गों का योग निम्न द्वारा दिया जाता है:
गणना:
माना Tn श्रृंखला का nवाँ पद है। तब,
Tn = (2n)2 = 4n2
∴ 22 + 42 + 62 + .... + (2n)2 =
इसलिए, श्रृंखला 22 + 42 + 62 + .... + (2n)2 का योग
Last updated on Jun 20, 2025
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