Question
Download Solution PDF(19 sin θ + 6 cot θ sin θ) का अधिकतम मान ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
व्यंजक: 19 sin θ + 6 cot θ sin θ
प्रयुक्त सूत्र:
a sin θ + b cos θ के रूप के व्यंजक का अधिकतम मान √(a² + b²) होता है।
गणनाएँ:
माना y = 19 sin θ + 6 cot θ sin θ
हम जानते हैं कि cot θ = cos θ / sin θ
प्रतिस्थापित करने पर, y = 19 sin θ + 6 (cos θ)
यहाँ, a = 19 और b = 6
अधिकतम मान = √(19² + 6²)
⇒ √(361 + 36) = √397
∴ (19 sin θ + 6 cot θ sin θ) का अधिकतम मान √397 है।
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