Question
Download Solution PDFDimension of specific heat is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF
विशिष्ट ऊष्मा धारिता: द्रव्यमान m वाले पदार्थ के तापमान को बढ़ाने के लिए आवश्यक ऊष्मा की मात्रा को विशिष्ट ऊष्मा कहा जाता है। इसे "C" या "S" द्वारा दर्शाया गया है।
S = (Q /m Δ t)
जहां S = किसी पदार्थ की विशिष्ट ऊष्मा, Q = निकाय को आपूर्त की गई उष्मा, m =पदार्थ का द्रव्यमान, Δ t =तापमान में परिवर्तन
व्याख्या:
ऊर्जा का आयामी सूत्र [E] = [ML2t-2]
S = (Q /m Δ t)
Q प्रदत्त उष्मा है जो एक प्रकार की ऊर्जा है
इसलिए [Q] = [E] = [ML2t-2]
[द्रव्यमान] = [M]
[तापमान] = [T]
Last updated on Jun 23, 2025
-> JKSSB JE application form correction facility has been started. Candidates can make corrections in the JKSSB recruitment 2025 form from June 23 to 27.
-> JKSSB Junior Engineer recruitment exam date 2025 for Civil and Electrical Engineering has been released on its official website.
-> JKSSB JE exam will be conducted on 10th August (Civil), and on 27th July 2025 (Electrical).
-> JKSSB JE recruitment 2025 notification has been released for Civil Engineering.
-> A total of 508 vacancies has been announced for JKSSB JE Civil Engineering recruitment 2025.
-> JKSSB JE Online Application form will be activated from 18th May 2025 to 16th June 2025
-> Candidates who are preparing for the exam can access the JKSSB JE syllabus PDF from official website of JKSSB.
-> The candidates can check the JKSSB JE Previous Year Papers to understand the difficulty level of the exam.
-> Candidates also attempt the JKSSB JE Mock Test which gives you an experience of the actual exam.