Question
Download Solution PDFएक ठोस शंकु जिसका वक्र पृष्ठीय क्षेत्रफल उसके आधार के क्षेत्रफल का दोगुना है, तथा उसकी तिर्यक ऊंचाई 6√3 सेमी है। इसकी ऊंचाई है:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
शंकु का वक्र पृष्ठीय क्षेत्रफल = 2 × शंकु के आधार का क्षेत्रफल
प्रयुक्त संकल्पना:
प्रयुक्त सूत्र
शंकु की तिर्यक ऊंचाई (l) = √r2 + h2
शंकु का वक्र पृष्ठीय क्षेत्रफल = πrl
गणना:
माना शंकु की त्रिज्या r इकाई है।
⇒ πrl = 2πr2
⇒ l = 2r
⇒ r = 6√3/2
⇒ r = 3√3
शंकु की तिर्यक ऊंचाई (l) = √r2 + h2
⇒ 6√32 = 3√32 + h2
⇒ h2 = 108 - 27 = 81
⇒ h = 9 सेमी
∴ उत्तर 9 सेमी है।
Last updated on Jun 13, 2025
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