Question
Download Solution PDFदो-पोर्ट नेटवर्क का लघु-परिपथ प्रवेश्यता आव्यूह \(\left[ {\begin{array}{*{20}{c}} 0\\ {\frac{1}{2}} \end{array}\begin{array}{*{20}{c}} { - \frac{1}{2}}\\ 0 \end{array}} \right]\) है। दो-पोर्ट नेटवर्क _________ है।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
प्रवेश्यता आव्यूह:
- इसे लघु परिपथ आव्यूह या Y आव्यूह के रूप में भी जाना जाता है।
- Y आव्यूह को इस प्रकार दर्शाया गया है:
\(\begin{bmatrix} Y_{11} & Y_{12}\\ Y_{21}& Y_{22} \end{bmatrix}\)= \(\begin{bmatrix} Y_{A}+ Y_{C}& -Y_{C}\\ -Y_{C}& Y_{B}+ Y_{C} \end{bmatrix}\)
- Y मापदंडों में सममितता और व्युत्क्रमता की स्थिति इस प्रकार दी गई है:
सममित: \(Y_{11}= Y_{22}\)
व्युत्क्रमता: \(Y_{12}= Y_{21}\)
व्याख्या:
दिया गया है कि Y आव्यूह \(\left[ {\begin{array}{*{20}{c}} 0\\ {\frac{1}{2}} \end{array}\begin{array}{*{20}{c}} { - \frac{1}{2}}\\ 0 \end{array}} \right]\) है
यहाँ, \(Y_{12}\neq Y_{21}\)
इसलिए Y आव्यूह व्युत्क्रम नहीं है।
शंट प्रवेश्यता ऊर्जा को नष्ट कर देता है, इसलिए यह एक निष्क्रिय तत्व है।
अतः विकल्प 1 सही है।
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