Question
Download Solution PDFA एक लक्ष्य को 6 में से 5 बार, B 5 में से 4 बार और C 4 में से 3 बार निशाना लगा सकता है। इसकी क्या प्रायिकता है कि A और C निशाना लगा सकते हैं लेकिन B नहीं?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFव्याख्या:
यहाँ, P(A) = 5/6 , P(B) = 4/5 , P(C) = 3/4
इसके अलावा
P(B) = \(1 - \frac{4}{5} = \frac{1}{5}\)
अब
⇒ \(P ( A\cap \overline{B} \cap C) = P(A).P(B).P(C)\)
= \(\frac{5}{6}\times \frac{1}{5}\times \frac{3}{4} = \frac{1}{8}\)
∴ विकल्प (a) सही है।
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