1111 + 12121 + 1020102 = ?

This question was previously asked in
NPCIL Assistant Grade-1 (Advance) Official Paper-II (Held On: 08 Sept, 2018)
View all NPCIL Assistant Grade 1 Papers >
  1. 1033334
  2. 1033344
  3. 103334
  4. 1303334

Answer (Detailed Solution Below)

Option 1 : 1033334
Free
NPCIL Assistant Grade 1 Computer Knowledge Subject Test - 01
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20 Questions 60 Marks 15 Mins

Detailed Solution

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दिया गया है:

1111 + 12121 + 1020102 = ?

प्रयुक्त सूत्र:

संख्याओं का साधारण योग

गणना:

1111 + 12121 + 1020102

⇒ 1111

⇒ + 12121

⇒ + 1020102

⇒ 1033334

∴ सही उत्तर विकल्प (1) है।

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