Two numbers are in ratio 5 : 8, If their difference is 48, then the smallest numbers is _____

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NPCIL Assistant Grade-1 (Advance) Official Paper-II (Held On: 08 Sept, 2018)
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  1. 64
  2. 80
  3. 96
  4. 128

Answer (Detailed Solution Below)

Option 2 : 80
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Detailed Solution

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Given:

Two numbers are in the ratio 5 : 8

Their difference is 48

Formula used:

Let the two numbers be 5x and 8x

Difference = 8x - 5x = 48

Calculation:

8x - 5x = 48

⇒ 3x = 48

⇒ x = 48 / 3

⇒ x = 16

The smallest number is 5x

⇒ 5 × 16 = 80

∴ The correct answer is option (2).

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