For a transmission line if \(\frac{\text{L}}{\text{C}}=\frac{\text{R}}{\text{G}}\) then incorrect statement is

  1. The line is called distortionless line
  2. If a series of pulses are transmitted they arrive undistorted
  3. \(​\text{Z}_{0}^{2}\) = R/G
  4. The line is lossless
  5. G = \(R \over Z^{2}\)

Answer (Detailed Solution Below)

Option 4 : The line is lossless
Free
RRB JE CBT I Full Test - 23
14.2 K Users
100 Questions 100 Marks 90 Mins

Detailed Solution

Download Solution PDF

Concept:

The characteristic impedance of a transmission line is defined as:

\({Z_0} = \sqrt {\frac{{R' + j\omega L'}}{{G' + j\omega C'}}} \)    ---(1)

And the propagation constant of the transmission line is defined as:

\(\gamma = \alpha + j\beta = \sqrt {\left( {R' + j\omega C'} \right)\left( {G' + j\omega C'} \right)} \)    ---(2)

Where,

α is attenuation constant

β is phase constant

R’ = Resistance per unit length of the line

G’ is conductance per unit length of the line

L’ is the inductance per unit length of the line

C’ is the capacitance per unit length of the line

Analysis:

distortion less line satisfies the following condition:

\(\frac{{R'}}{{L'}} = \frac{{G'}}{{C'}}\)

So, the characteristic impedance of the distortionless line will be:

\({Z_0} = \sqrt {\frac{{L'}}{{C'}}} = \sqrt {\frac{{R'}}{{G'}}} \)

∴ The characteristic impedance of both lossless and a distortionless line is real.

And the propagation constant of the distortion less line will be:

\(\gamma = \alpha + j\beta = \sqrt {R'G'} + j\omega \sqrt {L'C'} \)

\(\alpha = \sqrt {R'G'} \ne 0\)

Therefore, the attenuation constant of distortion less line is not zero but it is real.

As the line is distortionless, if a series of pulses are transmitted they arrive undistorted.

Important Points

For a lossless line:

R’ = G’ = 0

So, the characteristic impedance of a lossless transmission line using Equation (1) will be:

\({Z_0} = \sqrt {\frac{{L'}}{{C'}}} \)

And the propagation constant of a lossless transmission line using Equation (2) will be:

\(\gamma = \alpha + j\beta = j\omega \sqrt {L'C'} \)

α = 0

Therefore, the attenuation constant of the lossless line is always zero (real).

Latest SSC JE EE Updates

Last updated on May 29, 2025

-> SSC JE Electrical 2025 Notification will be released on June 30 for the post of Junior Engineer Electrical/ Electrical & Mechanical.

-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.

-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31. 

-> Candidates with a degree/diploma in engineering are eligible for this post.

-> The selection process includes Paper I and Paper II online exams, followed by document verification.

-> Prepare for the exam using SSC JE EE Previous Year Papers.

More Transmission and Distribution Questions

Get Free Access Now
Hot Links: teen patti cash game teen patti octro 3 patti rummy teen patti gold real cash teen patti master apk teen patti 51 bonus