Find the centroid of the triangle having vertices P(1, 3), Q(3, 6) and R(- 4, 0)?

Concept:

Centroid of a triangle:

If the three vertices of the triangle are A(x1, y1), B(x2, y2), C(x3, y3) then the centroid of a triangle = \(\rm (\frac{x_{1}+x_{2}+x_{3}}{3}, \frac{y_{1}+y_{2}+y_{3}}{3}).\)

Calculation:

Given: P(1, 3), Q(3, 6) and R(- 4, 0)

As we know that, the centroid of a triangle whose vertices are A(x1, y1), B(x2, y2), C(x3, y3) is given by: \(\rm (\frac{x_{1}+x_{2}+x_{3}}{3}, \frac{y_{1}+y_{2}+y_{3}}{3}).\)

Let the centroid of a triangle be S.

\(\Rightarrow \rm S=(\frac{1+3-4}{3}, \frac{3+6+0}{3} )=(0, 3)\)

Hence, the correct option is 2.