Question
Download Solution PDFConsider a CSMA/CD network that transmits data at a rate of 100 Mbps (10^8 bits per second) over a 1 km (kilometer) cable with no repeaters. If the minimum frame size required for this network is 1250 bytes, what is the signal speed (km/sec) in the cable?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFB = 108 bits/sec
d = 1 km
Round trip distance = 2 km
To detect a collision, the sender must be transmitting when it receives the collision signal so that it can transmit again.
\(\begin{array}{l} \therefore \frac{{1250 \times 8}}{{{{10}^8}}} = \frac{2}{{speed}}\\ \therefore speed = \frac{{2 \times {{10}^8}}}{{{{10}^4}}} = 2 \times {10^4 } \end{array}\)
Last updated on Jan 8, 2025
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