Question
Download Solution PDFCapacitance between the two conductors of a single-phase two-wire line is 1 μF/km. What will be the capacitance of each conductor to the neutral?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
Consider two conductors A and B, kept at a distance of 'D'.
In the given figure, CAN and CBN represent the line to neutral capacitance.
CAB represents the line-to-line capacitance.
\(C_{AN}=C_{BN}=2C_{AB}\)
Calculation
Given, \(C_{AB}=1\mu F/km\)
\(C_{AN}=C_{BN}=2(1)\space \mu F/km\)
\(C_{AN}=C_{BN}=2\space \mu F/km\)
Mistake Points Since capacitance is inversely proportional to impedance.
∴ CAN and CBN connected in series are not equal rather the correct expression is:
\(C_{AN}=C_{BN}=2C_{AB}\)
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