যদি (a + b + c) = 19 এবং (a2 + b2 + c2) = 155 হয়, তাহলে (a - b)2 + (b - c)2 + (c - a)এর মান নির্ণয় করুন।

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SSC CGL 2023 Tier-I Official Paper (Held On: 18 Jul 2023 Shift 2)
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  1. 104
  2. 108
  3. 100
  4. 98

Answer (Detailed Solution Below)

Option 1 : 104
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Detailed Solution

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প্রদত্ত:

(a + b + c) = 19

(a2 + b2 + c2) = 155

অনুসৃত সূত্র:

a2 + b2 + c2 - (ab + bc + ca) = (1/2) × [(a - b)2 + (b - c)2 + (c - a)2]

গণনা:

a + b + c = 19

উভয়পক্ষকে বর্গ করে পাই,

⇒ (a + b + c)2 = (19)2

⇒ a2 + b2 + c2 + 2 × (ab + bc + ca) = 361

⇒ 155 + 2 × (ab + bc + ca) = 361

⇒ 2 × (ab + bc + ca) = (361 - 155)

⇒ (ab + bc + ca) = 206/2 = 103

অতএব,

a2 + b2 + c2 - (ab + bc + ca) = (1/2) × [(a - b)2 + (b - c)2 + (c - a)2]

⇒ 2 × (155 - 103) = (a - b)2 + (b - c)2 + (c - a)2

⇒ (a - b)2 + (b - c)2 + (c - a)2 = 104

∴ সঠিক উত্তর হল 104

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