k এর 200% - 50 এর (k + 2)% = k হলে, k এর মান কত?

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SSC GD Constable Previous Year Paper (Held on: 13th December 2021 Shift 3) 
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  1. \(\frac{2}{3}\)
  2. \(\frac{100}{149}\)
  3. 2
  4. 1

Answer (Detailed Solution Below)

Option 3 : 2
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গণনা:

k এর 200% - 50 এর (k + 2)% = k

⇒ \(\dfrac{200}{100}\) × k - \(\dfrac{(k + 2)}{100}\) × 50 = k

⇒ 2k - (k + 2)/2 = k

⇒ 4k - k - 2 = 2k

⇒ 4k - 2k - k = 2

⇒ 4k - 3k = 2

⇒ k = 2

∴ k এর মান হল 2

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