Question
Download Solution PDFAtay of light passes from the air (refractive index 1.00) to water (refractive index 1.33). The ratio (v1/v2) of the speed of light in the air (v1) to that in water (v2) is ______ and the ray bends _______ the normal after refraction.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is 1.33; towards.
Key Points
- The speed of light in a medium is inversely proportional to the refractive index of the medium.
- The refractive index of air is 1.00 and that of water is 1.33.
- The ratio of the speed of light in air (v1) to that in water (v2) is given by v1/v2 = n2/n1 = 1.33/1.00 = 1.33.
- When light passes from a medium with a lower refractive index to a medium with a higher refractive index, it slows down and bends towards the normal.
- Hence, the ray of light bends towards the normal when it passes from air to water.
Additional Information
- Snell's Law
- It states that the ratio of the sines of the angles of incidence and refraction is constant, and equivalent to the ratio of the phase velocities in the two media.
- It is given by the formula: n1 sin(θ1) = n2 sin(θ2).
- Critical Angle
- The angle of incidence above which total internal reflection occurs.
- It occurs when light passes from a medium with a higher refractive index to one with a lower refractive index.
- Dispersion
- It is the phenomenon in which the phase velocity of a wave depends on its frequency.
- In optics, dispersion is most often described as the wavelength-dependent refractive index of a material.
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