Question
Download Solution PDFAnil and Tirath drove between two points A and B 192 km apart. Anil started the journey from point A at 8:20 a.m.; drove at a speed of 64 km/h; reached point B and immediately returned to A at the same speed. Tirath started the journey from point A at 9:50 a.m.; drove at a speed of 96 km/h; reached point B and immediately returned to A at the same speed. At what time did Anil and Tirath first meet each other?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Anil and Tirath drove between two points A and B 192 km apart.
Anil started the journey from point A at 8:20 a.m.; drove at a speed of 64 km/h; reached point B and immediately returned to A at the same speed.
Tirath started the journey from point A at 9:50 a.m.; drove at a speed of 96 km/h; reached point B and immediately returned to A at the same speed.
Calculation:
Anil takes to reach B 192 / 64 = 3hr
Tirath takes to reach 192 km i.e 192 / 96 = 2 hr
They will definitely meet in between 11:20 to 11:50
At 11:20 am the distance covered by Tirath is (192/120) × 90 = 144 km
Relative distance 192 - 144 = 48 km
Now relative speed is 96 + 64 = 160 km/hr
So time taken to cover 48 km is (60/160) × 48 = 18 mnts
So they will meet 18 minutes past 11:20
Time will be 11:20 am + 18minutes = 11: 38am
The correct option is A.
Last updated on Jun 13, 2025
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