An oscilloscope displays a 50 Hz, 20 V peak-to-peak sine waveform. Identify the reading in a digital multimeter for the same signal.

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ALP CBT 2 Electronic Mechanic Previous Paper: Held on 21 Jan 2019 Shift 1

Answer 1

Concept:

The oscilloscope displays the peak to peak waveform.

Digital multimeter reads the average value of the waveform.

The average value of the sinusoidal waveform:

\({V_{avg}} = \frac{{2{V_p}}}{\pi }\)

Where V_p is the peak value

Calculation:

Peak to peak value = 20 V

Peak value = 10 V

The average value of the given sinusoidal waveform:

\({V_{avg}} = \frac{{2 \times 10}}{\pi } = 6.36\;V\)