Question
Download Solution PDFAn electric charge +q moves with the velocity of 10 m/s parallel to the magnetic field. If the intensity of the magnetic field is 1 Tesla, find the force experienced by the particle.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
- While moving through a magnetic field, the charged particle experiences a force.
- This force is given by the charge times the vector product of velocity and magnetic field.
\(F = q (\vec{v}× \vec{B})\)
F = qvB sinθ
where q is the charge on particle, v is perpendicular velocity, B is the magnetic field, and θ is the angle between velocity and magnetic field.
EXPLANATION:
Given that velocity is parallel to the magnetic field, so θ = 0°
The force experienced by the particle is
F = qvB sinθ
here θ is the angle between velocity and magnetic field and θ = 0°
F = qvB sin0° = qvB × 0
F = 0
So the correct answer is option 1.
Last updated on May 31, 2025
-> The Indian Navy SSR Agniveeer Merit List will be released soon on the official website.
-> The Indian Navy Agniveer SSR CBT Exam was conducted from 25th to 26th May 2025.
->The application window was open from 29th March 2025 to 16th April 2025.
-> The Indian Navy SSR Agniveer Application Link is active on the official website of the Indian Navy.
.->Only unmarried males and females can apply for Indian Navy SSR Recruitment 2025.
-> The selection process includes a Computer Based Test, Written Exam, Physical Fitness Test (PFT), and Medical Examination.
->Candidates Qualified in 10+2 with Mathematics & Physics from a recognized Board with a minimum 50% marks in aggregate can apply for the vacancy.
-> With a salary of Rs. 30,000, it is a golden opportunity for defence job seekers.
-> Candidates must go through the Indian Navy SSR Agniveer Previous Year Papers and Agniveer Navy SSR mock tests to practice a variety of questions for the exam.