Question
Download Solution PDFAn eight pole D.C. generator has a simple wave wound armature containing 32 coils of 6 turns each. Its flux per pole is 0.06 wb. The machine is running at 250 rpm. The induced armature voltage is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFTotal No, of conductor = coil × turn × 2 = 32 × 6 × 2 = 384
ϕ = Flux, N = speed, P = Number of poles, A = Number of parallel paths, Z = Number of conductors
Induced armature voltage \(= \left( {\frac{{\phi ZN}}{{60}}} \right)\left( {\frac{P}{A}} \right)\)
\(= \frac{{0.06 \times 384 \times 250}}{{60}} \times \frac{8}{2}\)
(For wave wound A = 2) = 384Last updated on May 28, 2025
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