Question
Download Solution PDFAman can do a piece of work in 24 day, Bijay in 32 days and Chintu in 64 days. All begin to do it together, but Aman leaves after 6 days and Bijay leaves 6 days before the completion of the work. How many days did the work last?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Aman's work days = 24
Bijay's work days = 32
Chintu's work days = 64
Aman leaves after 6 days
Bijay leaves 6 days before completion
Formula used:
Total work = LCM of work days
Efficiency = Total work / Work days
Calculations:
Let total work = 192 units (LCM(24, 32, 64) = 192)
Aman's efficiency = 192 / 24 = 8 units/day
Bijay's efficiency = 192 / 32 = 6 units/day
Chintu's efficiency = 192 / 64 = 3 units/day
Work done by all in 6 days = 6 × (8 + 6 + 3) = 6 × 17 = 102 units
Remaining work = 192 - 102 = 90 units
Let the total number of days be x.
Bijay worked for (x - 6) days.
Chintu worked for x days.
Work done by Bijay and Chintu = 6 × (x - 6) + 3 × x = 90
⇒ 6x - 36 + 3x = 90
⇒ 9x - 36 = 90
⇒ 9x = 126 = 14
∴ The work lasted for 14 days.
Last updated on Jul 4, 2024
-> The JK Police SI applications process has started on 3rd December 2024. The last date to apply is 2nd January 2025.
-> JKSSB Sub Inspector Notification 2024 has been released for 669 vacancies.
-> Graduates between 18-28 years of age who are domiciled residents of Jammu & Kashmir are eligible for this post.
-> Candidates who will get the final selection will receive a JKSSB Sub Inspector Salary range between Rs. 35,700 to Rs. 1,13,100.