A voltmeter of resistance 150 Ω is connected across A and B in the given circuit. The reading of voltmeter will be :

F1 Madhuri UG Entrance 19.04.2023 D10

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CUET Physics 18th Aug 2022 Official Paper
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  1. 40 V
  2. 20 V
  3. 15 V
  4. 25 V

Answer (Detailed Solution Below)

Option 3 : 15 V
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Detailed Solution

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Calculation:

We know that the voltmeter is always connected in parallel.

The voltmeter resistance is given as 150 Ω and is connected across AB.

This means 150 Ω  is connected in parallel with 100 Ω .

The resistance across AB will be a parallel combination of 150 and 100 Ω resistors.

The resistance across AB = (150) II (100) 

= 150*100/(150 + 100)

= 60 Ω .

The net resistance of the circuit would be series combination of 60 and 100 Ω .

R = 60 + 100 

= 160 Ω.

Current I = V/R

I = 40/160

= 0.25.

The voltage across AB will be the voltmeter reading which is equal to I*R.

Voltmeter reading = 0.25*60

= 15 Volts.

The correct answer is option (3)

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