A voltage of 230∠60° is applied to a current offering an impedance of 10 + j10 Ω. Find the expression for the current flowing through the circuit in polar form.

This question was previously asked in
SSC JE Electrical 9 Oct 2023 Shift 3 Official Paper-I
View all SSC JE EE Papers >
  1. 16.3∠15° leading 
  2. 23∠45° leading 
  3. 16.3∠15° lagging
  4. 16.3∠45° lagging

Answer (Detailed Solution Below)

Option 3 : 16.3∠15° lagging
Free
Electrical Machine for All AE/JE EE Exams Mock Test
20 Qs. 20 Marks 20 Mins

Detailed Solution

Download Solution PDF

Conversion from rectangular form to polar form

The rectangular form of a coordinate is represented by 

The polar form of a coordinate is represented by 

where, 

Calculation

Given, Voltage =  230∠60° 

Z = 10 + j10 Ω = 10√2∠45° 

I = 16.3∠15°

The voltage phasor is 230∠60° and current phasor is 16.3∠15°. Taking the voltage as the reference, the current will lag the voltage by 45 degrees with an amplitude of 16.3 Amp.

Additional Information Conversion from polar to rectangular form

The polar form of a coordinate is represented by 

The rectangular form of a coordinate is represented by 

where, 

 

Latest SSC JE EE Updates

Last updated on Jul 1, 2025

-> SSC JE Electrical 2025 Notification is released on June 30 for the post of Junior Engineer Electrical, Civil & Mechanical.

-> There are a total 1340 No of vacancies have been announced. Categtory wise vacancy distribution will be announced later.

-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.

-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31. 

-> Candidates with a degree/diploma in engineering are eligible for this post.

-> The selection process includes Paper I and Paper II online exams, followed by document verification.

-> Prepare for the exam using SSC JE EE Previous Year Papers.

Hot Links: teen patti master plus teen patti joy vip teen patti real cash apk teen patti joy mod apk