Question
Download Solution PDFA string 2.0 m long and fixed at its ends is driven by a 240 Hz vibrator. The string vibrates in its third harmonic mode. The speed of the wave and its fundamental frequency is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Wave speed:
The speed of the wave is given by,
Wave speed = frequency × wavelength.
v = fλ
Wavelength (λ) is the distance between two corresponding points on adjacent waves. Wave frequency (f) is the number of waves that pass a fixed point in a given amount of time.
Fundamental Frequency:
The lowest frequency of any vibrating object is called the fundamental frequency.
i.e. the lowest frequency which is produced by the oscillation i.e., the fundamental frequency is given as,
\({f_1} = \frac{f}{n}\)
Calculation:
Given,
Frequency, f = 240 Hz
Length of the string, l = 2 m
The string vibrates in third harmonic mode i.e., n = 3
Standing waves of many different wavelengths can be produced on a string with two fixed ends, as long as an integral number of half wavelengths fits into the length of the string.
For a standing wave on a string of length L with two fixed ends, its wavelength will be
\(\lambda = \frac{{2l}}{n}\)
\(\lambda = 2 \times \frac{2}{3} = \frac{4}{3}\)
\(\lambda = \frac{4}{3}m\)
The speed of the wave is given by,
Velocity, \(v = f\lambda = 240 \times \frac{4}{3} = 320\) m/sec
By fundamental frequency formula,
\({f_1} = \frac{f}{n}\)
\({f_1} = \frac{{240}}{3} = 80\;{\rm{Hz}}\)
The speed of the wave and its fundamental frequency is 320 m/sec and 80 Hz respectively.Last updated on May 23, 2025
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