Question
Download Solution PDFA spark ignition engine has a compression ratio of 8 and the volume before compression is 0.9 m3/kg. Net heat interaction per cycle is 1575 kJ/kg. What is the mean effective pressure?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Compression ratio =
Work done = Mean effective pressure × swept volume
swept volume = (v1 – v2)
Calculation:
Given Compression ratio (r) = 8, v1 = 0.9 m3/kg, Net heat interaction for cycle = 1575 kJ/kg
For any cycle, the net heat interaction = Net work interaction
⇒
Work done = Mean effective pressure × swept volume (v1 – v2)
∴ 1575 × 103 = pm × (0.9 – 0.1125)
pm = 20 bar
Last updated on Jul 2, 2025
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