A solid cube is cut into two cuboids of equal volume. What is the ratio of total surface area of the given cube to that of one of the cuboids ?

Formula used:

Volume of cube of side a = a³

Total Surface area of cube = 6a²

Volume of cuobid of dimensione L, B & H = LBH 

Total surface area = 2 (LB + BH + HL)

Calculation:

Side of the cube = a.

Volume of the cube = a³

Volume of each cuboid = a³/2

Dimensions of each cuboid = a × a × a/2

Total surface area of the cube = 6 × a²

Total surface area of one cuboid

⇒ 2[a × a + a × (a/2) + a × (a/2)] = 4a² 

∴ Required ratio = 6a² : 4a² = 3 : 2